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Q.

$Δ H_{f}^{\circ}$ of water is $- 285.5 k J m o l^{- 1}$ . If enthalpy of neutralization of monoacidic strong base is $- 57.3 k J m o l^{- 1}$ , then, $Δ H_{f}^{\circ}$ of $O H^{-}$ ion will be :

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a

$- 228.5 k J m o l^{- 1}$

b

$114, 5 k J m o l^{- 1}$

c

$228.5 k J m o l^{- 1}$

d

$- 114, 5 k J m o l^{- 1}$

answer is A.

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Detailed Solution

The reaction is having follows,

$H^{+} + {OH}^{-} ⟶ H_{2} O$

$- 57.3 = - 285.5 - x$

$x = - 228.5$

Hence, option A is correct.

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