Hg2Cl2(s)+2e−→ 2Hg(l)+2Cl−; Eo=+0.27 VHg22+(aq)→ 2Hg2+(aq)+2e−;Eo=−0.92 V2Hg(l)→Hg2(aq)2++2e−;Eo=−0.79 VHg2Cl2(s)+2e−→ 2Hg(l)+2Cl−(saturated)Cl2(g)+2e−→ 2Cl−(aq);Eo=+1.36V2.303 RT/F=0.06,pressure is at 1 bar. By using the above data, identify among the following which is/are correct?

A) EHg2+/Hgo=+0.92×1+0.79×12=+0.855 VB) Hg2Cl2(s)+2e−→ 2Hg(l)+2Cl−;ΔG°=−2×F×0.27=−0.54F 2Hg(l)→ 2Hg2+4e−; ΔG°=−4×F×−0.855=+3.42 F Cl2+2e−→ 2Cl−; ΔG°=−2×F×1.36=−2.72F Hg2Cl2(s)+Cl2→ 2Hg2++4Cl−; ΔG°=+0.16F −2F Ecell°=+0.16F ⇒Ecello=−0.08VD) ECl−/Hg2Cl2/Hgo=EHg22+/Hgo+0.062log(K.sp)Hg2Cl2 +0.27=+0.79+0.03 log(Ksp)Hg2Cl2 Ksp of Hg2Cl2=10−17.3C) ECl−/Hg2Cl2/Hg=ECl−/Hg2Cl2/Hgo−0.062log[Cl−]2 +0.24=+0.27−0.03 log[Cl−]2 −0.03=0.03 log[Cl−]2 [Cl−]=10 M

Hg2Cl2(s)+2e−→ 2Hg(l)+2Cl−; Eo=+0.27 VHg22+(aq)→ 2Hg2+(aq)+2e−;Eo=−0.92 V2Hg(l)→Hg2(aq)2++2e−;Eo=−0.79 VHg2Cl2(s)+2e−→ 2Hg(l)+2Cl−(saturated)Cl2(g)+2e−→ 2Cl−(aq);Eo=+1.36V2.303 RT/F=0.06,pressure is at 1 bar. By using the above data, identify among the following which is/are correct?

A) EHg2+/Hgo=+0.92×1+0.79×12=+0.855 VB) Hg2Cl2(s)+2e−→ 2Hg(l)+2Cl−;ΔG°=−2×F×0.27=−0.54F 2Hg(l)→ 2Hg2+4e−; ΔG°=−4×F×−0.855=+3.42 F Cl2+2e−→ 2Cl−; ΔG°=−2×F×1.36=−2.72F Hg2Cl2(s)+Cl2→ 2Hg2++4Cl−; ΔG°=+0.16F −2F Ecell°=+0.16F ⇒Ecello=−0.08VD) ECl−/Hg2Cl2/Hgo=EHg22+/Hgo+0.062log(K.sp)Hg2Cl2 +0.27=+0.79+0.03 log(Ksp)Hg2Cl2 Ksp of Hg2Cl2=10−17.3C) ECl−/Hg2Cl2/Hg=ECl−/Hg2Cl2/Hgo−0.062log[Cl−]2 +0.24=+0.27−0.03 log[Cl−]2 −0.03=0.03 log[Cl−]2 [Cl−]=10 M

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${Hg}_{2} {Cl}_{2} (s) + 2 e^{-} \to_{}^{} 2 Hg (l) + 2 {Cl}^{-}; E^{o} = + 0.27 V$
${Hg}_{2}^{2 +} (aq) \to_{}^{} 2 {Hg}^{2 +} (aq) + 2 e^{-}; E^{o} = - 0.92 V$
$2 Hg (l) \to {Hg}_{2 (aq)}^{2 +} + 2 e^{-}; E^{o} = - 0.79 V$
${Hg}_{2} {Cl}_{2} (s) + 2 e^{-} \to_{}^{} 2 Hg (l) + 2 {Cl}^{-} (saturated)$
${Cl}_{2} (g) + 2 e^{-} \to_{}^{} 2 {Cl}^{-} (aq); E^{o} = + 1.36 V$

$2.303 RT / F = 0.06,$ pressure is at 1 bar. By using the above data, identify among the following which is/are correct?

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${Hg}_{2} {Cl}_{2} (s) + {Cl}_{2} (s) \to_{}^{} 2 {Hg}^{2 +} (aq) + 4 {Cl}^{-} (aq)$

$E_{cell}^{o} = - 0.08 V$

Conc. of KCl in saturated KCl of Calomel electrode saturated with KCl is $\sqrt{10} M$

$E_{{Hg}^{2 +} / Hg}^{o} = + 0.855 V$

$K_{sp} of {Hg}_{2} {Cl}_{2}$ is nearly $10^{- 17.33}$

answer is A, B, C, D.

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Detailed Solution

A) $E_{{Hg}^{2 +} / Hg}^{o} = \frac{+ 0.92 \times 1 + 0.79 \times 1}{2} = + 0.855 V$
B) ${Hg}_{2} {Cl}_{2} (s) + 2 e^{-} \to_{}^{} 2 Hg (l) + 2 {Cl}^{-}; ΔG ° = - 2 \times F \times 0.27 = - 0.54 F 2 Hg (l) \to_{}^{} 2 {Hg}^{2 +} 4 e^{-}; ΔG ° = - 4 \times F \times - 0.855 = + 3.42 F {Cl}_{2} + 2 e^{-} \to_{}^{} 2 {Cl}^{-}; ΔG ° = - 2 \times F \times 1.36 = - 2.72 F {Hg}_{2} {Cl}_{2} (s) + C l_{2} \to_{}^{} 2 {Hg}^{2 +} + 4 {Cl}^{-}; ΔG ° = + 0.16 F - 2 F E_{cell}^{°} = + 0.16 F \Rightarrow E_{cell}^{o} = - 0.08 V$
D) $E_{{Cl}^{-} / {Hg}_{2} {Cl}_{2} / Hg}^{o} = E_{{Hg}_{2}^{2 +} / Hg}^{o} + \frac{0.06}{2} \log {(K . sp)}_{{Hg}_{2} {Cl}_{2}} + 0.27 = + 0.79 + 0.03 \log {(K_{sp})}_{{Hg}_{2} {Cl}_{2}} K_{sp} of {Hg}_{2} {Cl}_{2} = 10^{- 17.3}$
C) $E_{{Cl}^{-} / {Hg}_{2} {Cl}_{2} / Hg} = E_{{Cl}^{-} / {Hg}_{2} {Cl}_{2} / Hg}^{o} - \frac{0.06}{2} \log {[{Cl}^{-}]}^{2} + 0.24 = + 0.27 - 0.03 \log {[{Cl}^{-}]}^{2} - 0.03 = 0.03 \log {[{Cl}^{-}]}^{2} [{Cl}^{-}] = \sqrt{10} M$