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Q.

${Hg}_{2} I_{2} ↓ (green) \frac{Boiled}{with H_{2} O} Products$
Which of the following statement is correct with respect to the products?

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a

Violet colour gas is evolved

b

Red precipitate of ${HgI}_{2}$ is formed

c

Mercury is obtained

d

Black precipitate of mercury(I) oxide is formed

answer is C, D.

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Detailed Solution

Complete reaction is,

${Hg}_{2} I_{2} \to_{with H_{2} O}^{Boiled} Hg ↓ + {HgI}_{2} ↓$

Here, c and d are correct.

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