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Q.

HgCl₂ is a covalent compound, sparingly soluble in water, the solubility increases by the addition of chloride ions due to :

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a

strong ion-dipole forces

b

common ion effect

c

formation of complex ${[{HgCl}_{4}]}^{2 -}$

d

weakening of Hg-Cl bonds

answer is B.

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Detailed Solution

${HgCl}_{2} + \underset{(Excess)}{2 {Cl}^{-}} ⟶ {[{HgCl}_{4}]}^{2 -}$

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