High temperature and high pressure (as per Le Chatelier's principle) favor,

 The reaction, $3O_2\rightleftharpoons 2O_3, ∆H = +Q3$

In the above reaction , see how there are 3 molecules in the reaction on the left side of the equation, but only 2 on the right. Le Chatelier's Principle states that the system will react by favoring the reaction that generates the fewest molecules. The pressure and temperature will increase once again as a result of that. As a result, the response will favor the goods more.

Therefore, the correct answer is option (C) $3O_2\rightleftharpoons 2O_3, ∆H = +Q3$