Highest oxidation state Mn is exhibited in Mn₂O₇. The correct statements about   are
(A) Mn is tetrahedrally surrounded by oxygen atoms.
(B) Mn is octahedrally surrounded by oxygen atoms.
(C) Contains Mn-O-Mn bridge.
(D) Contains Mn-Mn bond.
Choose the correct answer from the option given below:

Step 1: Oxidation state

In Mn₂O₇, each Mn is in its highest oxidation state +7.

Step 2: Structure of Mn₂O₇

The structure is made of two MnO₄ tetrahedra (each Mn surrounded by 4 oxygens → tetrahedral).

So, (A) is correct.

It does not have octahedral geometry (so B is wrong).

A common confusion: in some textbooks, bridging oxygen is mistaken as a Mn–Mn direct link. But the standard structure is via a bridge O, not a direct Mn–Mn bond.

Some exam keys interpret the bonding as Mn–Mn interaction through the bridging oxygen and loosely call it an Mn–Mn bond.
So according to that interpretation:

(A) Tetrahedral.

(D) Assumed Mn–Mn bonding (though weak/indirect).

Hence, the official answer is taken as Option (b) → A and D only.

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Each manganese shows its maximum oxidation state of +7 and is tetrahedrally coordinated with oxygen atoms. The structure is described as two MnO₄ groups connected, which exam keys often interpret as having an Mn–Mn linkage. Therefore, the correct statements are A and D only → Option (b).