${\mathrm{HNO}}_2\left(l\right)+\mathrm{NaCl}\left(s\right)⟶\mathrm{HCl}\left(g\right)+{\mathrm{NaNO}}_2\left(s\right)$

Calculate the $\mathrm{\Delta }{H}^{\circ }$ value for the reaction above from the information below :

Reaction	$\mathrm{\Delta }H\mathrm{kJ}\cdot {\mathrm{mol}}^{-1}$
$\mathrm{NO}\left(g\right)+{\mathrm{NO}}_2\left(g\right)+{\mathrm{Na}}_2\mathrm{O}\left(s\right) ⟶2{\mathrm{NaNO}}_2\left(s\right)$	-427.0
$\mathrm{NO}\left(g\right)+{\mathrm{NO}}_2\left(g\right)⟶{\mathrm{N}}_2\mathrm{O}\left(g\right)+{\mathrm{O}}_2\left(g\right)$	-43.0
$2\mathrm{NaCl}\left(s\right)+{\mathrm{H}}_2\mathrm{O}\left(l\right) ⟶2\mathrm{HCl}\left(g\right)+{\mathrm{Na}}_2\mathrm{O}\left(s\right)$	507.0
$2{\mathrm{HNO}}_2\left(l\right)⟶{\mathrm{N}}_2\mathrm{O}\left(g\right)+{\mathrm{O}}_2\left(g\right)+{\mathrm{H}}_2\mathrm{O}\left(l\right)$	34.0