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Q.

HNO3   oxidizes NH4+ ions to nitrogen and itself gets reduced to NO2.

The moles of HNO3 required by 1 mole of NH42SO4  is

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a

4

b

5

c

6

d

2

answer is C.

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Detailed Solution

HN+5O3+N-3H4+N02+N+4O2V.F.  ofHNO3=54=1V.F.  of  NH4+=03=3so  molar  ratio  ofHNO3  and  NH4+  is3:1.1moleNH42SO4  is  found  to  contain  2  mole  ofNH4+So,  required  moles  of  HNO3  is  3×  2=6  moles.

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