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Hot water of 50 g at $80 ° C$ cools down to $50 ° C$ . The amount of heat energy lost is (specific heat of water is ${1calg}^{- 1} ° c^{- 1}$ )

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800 cal

150 cal

2000 cal

1500 cal

answer is A.

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Detailed Solution

Mass m = 50g

$Δ T = 80 - 50 = 30 ° C$

$S_{w} = 1 {cal g}^{- 1} {°C}^{- 1}$

$Q = ms Δ t$

$Q = 50 \times 1 \times 30$

$Q = 1500 cal$

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