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How do you factor $x^{2} - 4 x + 3$ ?

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x^{2} - 4 x + 8

{2 x}^{2} - 3 x - 2

{4 x}^{2} - 6 x + 7

(x - 1) (x - 3)

answer is D.

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Detailed Solution

x = \frac{- b \pm \sqrt{b^{2} - 4 ac}}{2 a}

= \frac{- (- 4) \pm \sqrt{{(- 4)}^{2} - 4 \times 1 \times 3}}{2 \times 1}

= \frac{4 \pm \sqrt{16 - 12}}{2}

= \frac{4 \pm \sqrt{4}}{2}

= \frac{4 \pm 2}{2}

x = \frac{4 + 2}{2}

x = \frac{4 - 2}{2}

x = \frac{6}{2}

x = \frac{2}{2}

x - 3 = 0

x - 1 = 0

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