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How do you factorise the given polynomial completely: $4 x^{2} - 3 x - 1$ ?

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(5 x + 1) (5 x - 1)

(2 x + 2) (9 x - 2)

(4 x + 1) (x - 1)

(4 x + 1) (9 x - 1)

answer is C.

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Detailed Solution

f (x) = 4 x^{2} - 3 x - 1

= 4 x^{2} - 4 x + 1 x - 1

= 4 x (x - 1) + 1 (x - 1)

= (4 x + 1) (x - 1)

4 x + 1 = 0, x - 1 = 0

x = \frac{- 1}{4}, x = 1

∴ The factorization of the given polynomial is

(4 x + 1) (x - 1)

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