How do you find the factor 3x2 -8x+15?Sub Grade: 10

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How do you find the factor 3x2 -8x+15?

Sub Grade: 10

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\frac{8 \pm \sqrt{10.77}}{6}

\frac{4 \pm \sqrt{10.77}}{6}

\frac{6 \pm \sqrt{10.77}}{6}

\frac{2 \pm \sqrt{10.77}}{6}

answer is A.

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Detailed Solution

Given equation 3x2 -8x+15
Quardic formula=

\frac{- b \pm \sqrt{b^{2} - 4 ac}}{2 a}

Here a=3, b= -8 ,c= +15
⇒

\frac{- (- 8) \pm \sqrt{64 - 180}}{6}

⇒

\frac{8 \pm \sqrt{- 116}}{6}

⇒

\frac{8 \pm \sqrt{10.77}}{6}

∴ the root of factor is

\frac{8 + \sqrt{10.77}}{6}

and

\frac{8 - \sqrt{10.77}}{6}

Type Exam: CBSE

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