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How do you prove nCr=n! /r! (n-r)! With clear steps?
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Detailed Solution
The nCr formula, also known as the combination formula, calculates the number of ways to choose r items from n items where order does not matter. This fundamental concept is essential in combinatorics, probability theory, and statistical analysis.
Formulas Table
Formula Type | Mathematical Expression | Alternative Notation | Explanation |
Basic nCr Formula | nCr = n! / (r! × (n-r)!) | C(n,r) = n! / (r! × (n-r)!) | Number of combinations of n items taken r at a time |
nPr Formula | nPr = n! / (n-r)! | P(n,r) = n! / (n-r)! | Number of permutations of n items taken r at a time |
Relationship Formula | nCr = nPr / r! | C(n,r) = P(n,r) / r! | Combinations equals permutations divided by r factorial |
Factorial Definition | n! = n × (n-1) × (n-2) × ... × 2 × 1 | 0! = 1 (by definition) | Product of all positive integers up to n |
Essential Properties and Special Cases
Property/Case | Formula | Explanation | Example |
Symmetry Property | nCr = nC(n-r) | Choosing r items equals choosing (n-r) items to exclude | 5C2 = 5C3 = 10 |
Boundary Cases | nC0 = nCn = 1 | Only one way to choose nothing or everything | 7C0 = 7C7 = 1 |
Single Selection | nC1 = n | n ways to choose one item from n items | 8C1 = 8 |
Pascal's Identity | nCr = (n-1)Cr + (n-1)C(r-1) | Used to construct Pascal's triangle | 5C2 = 4C2 + 4C1 |
Sum Property | Σ(nCr) = 2ⁿ (r=0 to n) | Sum of all combinations equals 2 to the power n | 3C0 + 3C1 + 3C2 + 3C3 = 8 = 2³ |
Probability Applications
Application | Formula | Use Case | Example |
Basic Probability | P(Event) = nCr / Total Combinations | Calculating probability using combinations | P(2 heads in 4 flips) = 4C2 / 2⁴ |
Binomial Probability | P(X = k) = nCk × p^k × (1-p)^(n-k) | Probability of exactly k successes in n trials | P(exactly 3 successes in 10 trials) |
Hypergeometric | P(X = k) = (KCk × (N-K)C(n-k)) / NCn | Sampling without replacement | Drawing cards from a deck |
Advanced Relationships
Relationship | Formula | Mathematical Context |
Binomial Theorem | (a + b)ⁿ = Σ(nCr × aⁿ⁻ʳ × bʳ) | Expansion of binomial expressions |
Vandermonde's Identity | (m+n)Cr = Σ(mCk × nC(r-k)) | Sum over all valid k values |
Chu-Vandermonde | Σ(mCr × nCs) = (m+n)C(r+s) | When summing over specific ranges |
Computational Formulas for Large Numbers
Method | Formula | Advantage |
Multiplicative Form | nCr = (n × (n-1) × ... × (n-r+1)) / (r × (r-1) × ... × 1) | Avoids large factorial calculations |
Recursive Formula | nCr = (n × (n-1)C(r-1)) / r | Efficient for sequential calculations |
Logarithmic Form | log(nCr) = log(n!) - log(r!) - log((n-r)!) | For very large numbers to prevent overflow |
Mistakes to Avoid
Error Type | Incorrect | Correct | Note |
Order Confusion | Using nPr for unordered selection | Use nCr for combinations | Order doesn't matter in combinations |
Zero Factorial | 0! = 0 | 0! = 1 | By mathematical convention |
Negative Values | nCr where r > n | nCr = 0 when r > n | Cannot choose more than available |
Non-integer Values | Using decimals for n or r | Only use non-negative integers | Combinations require whole numbers |
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