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How do you solve √x + 3 = x - 3 and find any extraneous solution?
Sub Grade: 10

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x= 3

x= 6

x= 9

x= 12

answer is B.

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Detailed Solution

Given √x + 3 = x - 3
Now square both side to get
x+3 = x2 - 6x +9
Subtract x+3 from both side to get
0 = x2 - 7 x +6 = (x-1)(x-6)
This has two solution x= 1 ans x=6
But x=1 not solution of equation since we require x≥3
So x= 6
Type Exam: CBSE

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