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Q.

How do you solve 7x=80

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a

log8802.27

b

log10802.28

c

log7802.25

d

log6702.20 

answer is C.

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Detailed Solution

The equation is 7x=80
Substituting x=0
70=1
If x=1
71=7
If x=2
72=49
If 73=343
So, 80 lies between 72 and 73
So, by logarithm
log 80=1.903
log 7=0.845
Substituting the value
x=1.9030.845   log780
x=2.25
    
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