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How do you solve r+3 ≥7 ?
Sub Grade: 10

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(- \infty, - 10) (4, + \infty)

(- \infty, - 8) (3, + \infty)

(- \infty, - 11) (5, + \infty)

(- \infty, - 16) (8, + \infty)

answer is A.

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Detailed Solution

Given r+3 ≥7
-7 ≥ r+3 ≥7..(1)
Subtract 3 from each side in eq(1)
⇒-10 ≥ r+0 ≥4
⇒-10 ≥ r ≥4 or r ≤ -10 , r ≥ 4 or , in interval notation
⇒

(- \infty, - 10) (4, + \infty)

Type Exam: CBSE

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