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How do you solve $x^{2} - 2 x - 2$ to find value of $x$ .

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1 + \sqrt{3}

1 - \sqrt{3}

2 \sqrt{3}

Both 1) and 2)

answer is D.

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Detailed Solution

Given equation:

x^{2} - 2 x - 2

As we know basic formula of quadratic equation -

x = \frac{- b \pm \sqrt{b^{2} - 4 ac}}{2 a}

Here,

b = - 2

a = 1

c = - 2

Putting value of

a, b

and

c

in above equation

x = \frac{- (- 2) \pm \sqrt{{(- 2)}^{2} - 4 (1) (- 2)}}{2 (1)}

x = \frac{2 \pm \sqrt{4 + 8}}{2}

x = \frac{2 \pm \sqrt{12}}{2}

x = \frac{2 \pm 2 \sqrt{3}}{2}

x = \frac{2 (1 \pm \sqrt{3})}{2}

x = 1 \pm \sqrt{3}

Now, we have

x = 1 + \sqrt{3}, x = 1 - \sqrt{3}

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