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How does the force of gravitation between two objects change when the distance between them is reduced to half?

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2

times

4

times

\frac{1}{2}

times

\frac{1}{4}

times

answer is B.

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Detailed Solution

The force of gravitation between two objects becomes

4

times when the distance between them is reduced to half.
The force of gravitation between two objects is given by,

\Rightarrow F = \frac{G m_{1} m_{2}}{r^{2}}

,
Where

F, G, m_{1}, m_{2},

and

r

represents the force, universal gravitational constant, the mass of object one, the mass of object two and distance, respectively.
i.e.,

F \propto \frac{1}{r^{2}}

So, when

r

is reduced to

\frac{r}{2}

F

will become

\Rightarrow F = \frac{1}{{(\frac{1}{2})}^{2}}

\Rightarrow F = 4

times

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How does the force of gravitation between two objects change when the distance between them is reduced to half?

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