How long(approximate) should water be electrolysed by passing through 100 amperes current so that the oxygen released can completely burn 27.66 g of diborane ?(Atomic weight of B=10.8 u)

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6.4 hours

0.8 hours

3.2 hours

1.6 hours

answer is C.

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Detailed Solution

$\begin{array}{l} 1 B_{2} H_{6} + 3 O_{2} \to B_{2} O_{3} + 3 H_{2} O \\ 1 mole 3 mole \\ 2 H_{2} O \overset{4 F}{\to} 2 H_{2} + O_{2} \end{array}$
1 mole O₂ ----- 4F
3 mole O₂ ------12F
12 x 96500 O = 100 x t
t = 3.2hrs

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