How many alcohols with molecular formula $C_{4} H_{10} O$ are chiral in nature?

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answer is A.

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Detailed Solution

Given data : It is given to identify how many alcohols with molecular formulas $C_{4} H_{10} O$ are chiral, from the given option.

Explanation
Butanol is capable of having all three isomers. Below is the structural formula for these isomers.
i) $\underset{Butan-1-ol}{C H_{3} C H_{2} - C H_{2} - C H_{2} O H}$
In this compound, none of the four carbon atoms are bonded to any of the four different substituents, so no carbon is chiral.
ii) $\underset{Butan-2-ol}{C H_{3} - C H_{2} - \underset{O H}{\underset{∣}{\overset{*}{C H}}} - C H_{3}}$
The chiral carbon indicated by the asterisk in this compound is one with four distinct substituents attached to it.
iii) $\underset{2-methylpropan-2-ol}{H_{3} C - \underset{O H}{\underset{∣}{\overset{C H_{3}}{\overset{∣}{C}}}} - C H_{3}}$
Again, in this case, carbon is not chiral by nature.
Hence, the correct option (A). 1.