How many atoms are contained in one mole of sucrose $\left({\mathrm{C}}_{12}{\mathrm{H}}_{22}{\mathrm{O}}_{11}\right)?$

 1 mole of sucrose contains $6.023\times {10}^{23}$ molecules

$\because$    1 molecule of sucrose(${\mathrm{C}}_{12}{\mathrm{H}}_{22}{\mathrm{O}}_{11}$) has 45 atoms

$\therefore 6.023\times {10}^{23}\mathrm{molecule}\mathrm{of}\mathrm{sucrose}\mathrm{has}45\times 6.023\times {10}^{23}\mathrm{atoms}/\mathrm{mol}e$