How many atoms are present in 0.25 mole of SO3?

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6.02 × 1023

4.15 × 1023

1.505 × 1023

3.05 × 1022

answer is C.

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Detailed Solution

1.505 ×1023 atoms are present in 0.25 mole of SO3.
SO3 has 1 sulphur atom and 3 oxygen atoms in 1 molecule.
1 mole of any substance contains molecules =

6.022 \times 1 0^{23}

Number of atoms of sulphur in 0.25 mole of SO3 =

0.25 \times 6.022 \times 1 0^{23}

\Rightarrow

1.505 \times 1 0^{23} atoms

Number of atoms of oxygen in 0.25 mole of SO3 =

3 \times 0.25 \times 6.022 \times 1 0^{23}

\Rightarrow 4.515 \times 1 0^{23} at oms

3 is taken because 1 molecule of SO3 contains 3 oxygen atoms.
Total number of atoms in 0.25 moles of SO3

= (1.505 + 4.515) \times 10 ²³

\Rightarrow 6.02 \times 10 ²³

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