How many atoms of sodium (Na) are there in 92 amu. (Atomic mass of Na=23)

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answer is 4.

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Detailed Solution

To determine the number of sodium (Na) atoms in a given amount of 92 amu, we use the concept of atomic mass. The atomic mass of Na is defined as the mass of a single sodium atom, which is approximately 23 amu.

The formula to calculate the number of atoms is as follows:

Number of atoms = Total mass in amu / Atomic mass of Na

Here, the total mass provided is 92 amu, and the atomic mass of Na is 23 amu. Substituting the values:

Number of sodium atoms = 92 / 23

Performing the division gives:

Number of sodium atoms = 4

Therefore, there are 4 sodium (Na) atoms in 92 amu of mass. The atomic mass of Na plays a crucial role in this calculation as it provides the standard weight of one sodium atom, enabling us to determine how many such atoms are present in the given total mass.

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