How many bonding pairs and lone pairs surround the central atom in the 13 ion?

Bonding Pairs

Lone pairs

The reaction is,

$\mathrm{H}=\frac{1}{2}[\mathrm{V}+\mathrm{M}-\mathrm{C}+\mathrm{A}]$

where,
H stands for the number of orbitals that hybridization involved.
V: The core atom's valence electrons.
M: The total number of monovalent atoms connected to the main atom.
C = Cation's charge.
A is the anion's charge.
Think on the possibilities' hybridization and shape:

(A) ${{\mathrm{I}}_3}^{-}$

$\mathrm{H}=\frac{1}{2}[7+2+1]=5$.

${\mathrm{sp}}^3\mathrm{d}$ 3 lone pairs in a hybridised condition.
Shaped like a line.
Two bond pairs exist.