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How many cells each marked (6V – 12A) should be connected in mixed grouping so that it may be marked (24V – 24 A)

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answer is B.

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Detailed Solution

$\begin{array}{l} E_{net} = nE \Rightarrow 24 = 6 n \Rightarrow n = 4; r = \frac{E}{I} = \frac{6}{12} = \frac{1}{2} \\ R = 0 \Rightarrow i = \frac{mE}{r} \Rightarrow 2 mE = 24; n = 6; \\ Total cells = 4 \times 2 = 8 \end{array}$

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