How many different nine digit numbers can be formed from the number 223355888 by rearranging its digits so that the odd digits occupy even positions?

The four digits 3, 3, 5, 5 can be arranged at four even places in $\frac{4!}{2!2!}=6$ ways and the remaining digits viz., 2, 2, 8, 8, 8 can be arranged at the five odd places in $\frac{5!}{2!3!}=10$ ways.

Thus, the number of possible arrangements is (6) (10) = 60.