How many electrons are totally shared in a molecule of ${\mathrm{XeOF}}_4$ for the formation of bonds?

In ${\mathrm{XeOF}}_4$

Total number of electron pair $=\frac{8+0+4}{2}=6$

Total number of bond pair = 6

Total number of lone pair =(6-5)=1

Hybridization $={\mathrm{sp}}^3{ \mathrm{d}}^2$

Thus, the predicted shape is square pyramidal.

Overall electrons shared in a molecule $=4\times 2+4+2$

$=14$

Hence, 14 electrons are totally shared in a molecule of ${\mathrm{XeOF}}_4$ for the formation of bonds.