How many electrons constitute a current of one microampere

$i=1\times {10}^{-6}\text{A, t}=1\text{s}$

$i=\frac{\text{ne}}{\text{t}}$

$1\times {10}^{-6}=\frac{\text{n}\times \text{1}\text{.6}\times {\text{10}}^{-19}}{1}$

$\text{n}=0.625\times {10}^{-6}\times {\text{10}}^{19}$

$\text{n}=0.625\times {10}^{13}$

$\text{n}=6.25\times {10}^{12}$