How many geometrical isomers are possible for the square-planar complex [Pt(NO₂)(py)(NH₂OH)Cl] ?

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Eight

Three

Five

Four

answer is D.

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Detailed Solution

For the square planar complex [Mabcd] where M is the central atom and a,b,c,d are monodentate ligands, the number of possible geometrical isomers are three.

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