How many grams of concentrated nitric acid solution should be used to prepare 250 mL of 2.0 M ${HNO}_{3}$ ? The concentrated acid is 70% ${HNO}_{3}$

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$70 .0 g conc . {HNO}_{3}$

$54 .0 g conc . {HNO}_{3}$

$45 .0 g conc . {HNO}_{3}$

$90 .0 g conc . {HNO}_{3}$

answer is C.

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Detailed Solution

$Molarity = \frac{W \times 1000}{MW \times V_{sol (mL)}} \Rightarrow 2 = \frac{W}{63} \times \frac{1000}{250} W = \frac{63}{2} g Mass of acid \times \frac{70}{100} = \frac{63}{2} Mass of acid = 45 g$

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