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How many grams of glucose to be added to 0.5 liter of a solution so that its osmotic pressure is same as that of a solution of 9.2gm of glucose dissolved in a liter ?

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1.15

9.22

2.31

4.60

answer is D.

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Detailed Solution

$π_{1} = π_{2}$

${(\frac{n}{v})}_{1} = {(\frac{n}{v})}_{2}$

${(\frac{w}{v})}_{1} = {(\frac{w}{v})}_{2}$

$\frac{w}{0.5} = \frac{9.2}{1} \Rightarrow w = 4.6 g m$

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