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How many grams of ${MgC}_{2} O_{4}$ (formula weight = 112) will dissolve in 1.5 L of water ? ( $Ksp = 8 .1 \times 10^{-5}$ )

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1.512

4.65

1.29

1.0

answer is C.

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Detailed Solution

s² = 8.1 $\times$ 10^-3

s=9 $\times$ 10^-3

$9 \times 10^{- 3} = \frac{w}{112} \times \frac{1}{1.5}$

w=1.512 gm

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