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How many grams of ${CaC}_{2} O_{4}$ dissolve in distilled water to make one litre of saturated solution $(K_{sp} = 2.5 \times 10^{- 9} & its molecular mass is 128)$

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0.0640 g

0.0128 g

0.0032 g

0.0064 g

answer is A.

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Detailed Solution

${CaC}_{2} O_{4} ⇌ {Ca}^{+ 2} + C_{2} O_{4}^{- 2}$

$K_{Sp} = S^{2} \Rightarrow S = \sqrt{K_{Sp}} = \sqrt{2.5 \times 10^{- 9}} = 5 \times 10^{- 5} mol / lit$

GMW = 128

$5 \times 10^{- 5} = \frac{g}{GMW}$

$g = 5 \times 10^{- 5} \times 128 = 6.40 \times 10^{- 5} = 0.0064$

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