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Q.

How many grams of $H_{3} {PO}_{4}$ is required to completely neutralize 120g of NaOH

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a

9.8

b

49

c

98

d

196

answer is B.

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Detailed Solution

$H_{3} {PO}_{4} + 3 NaOH \to {Na}_{3} {PO}_{4} + 3 H_{2} O$

98 gram $3 \times 40 grams$

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