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Q.

How many H atoms are in $3.42 g$ of $C_{12} H_{22} O_{11}$ ?

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a

$6.0 \times 10^{23}$

b

$1.3 \times 10^{23}$

c

$3.8 \times 10^{22}$

d

$6.0 \times 10^{21}$

answer is B.

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Detailed Solution

H atoms are in 3.42 g of given molecule;

$\frac{3.42}{342} \times 22 \times 6.0 \times 10^{23}$

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