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How many Kilograms of Pure water to be added to 100 Kilograms of a 30% saline solution to make it a 10% saline solution.

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200

300

400

500

answer is A.

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Detailed Solution

Suppose that
The pure water to be added (x) = weight in kilograms
The weight in kg = y of 10% solution
Therefore from given condition,

x + 100 = y

In the saline solution the weight of salt present in 100 kg
= 30% of 100 kg

= \frac{30}{100} \times 100

= 30

the weight of the saline solution = 100 kg
When we adding x kg of pure water into 100 kg of a 30% saline solution, then
we obtain a 10% saline solution.

= (100 + x) kg

% of the salt adding in the new saline solution

(\frac{30}{100 + x} \times 100)

Now calculate the all value we get,

\Rightarrow 10 = \frac{30}{100 + x} \times 100

\Rightarrow 10 = \frac{3000}{100 + x}

\Rightarrow 10 (100 + x) = 3000

\Rightarrow 1000 + 10 x = 3000

\Rightarrow 10 x = 3000 - 1000

\Rightarrow 10 x = 2000

\Rightarrow x = \frac{2000}{10}

\Rightarrow x = 200

Correct option is 1.

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