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How many liters of ${CO}_{2}$ at STP will be formed when 100 ml. of 0.1 M $H_{2} {SO}_{4}$ reacts with excess of ${Na}_{2} {CO}_{3}$

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22.4

0.224

5.6

2.24

answer is C.

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Detailed Solution

${Na}_{2} {CO}_{3} + H_{2} {SO}_{4} \to {Na}_{2} {SO}_{4} + H_{2} O + {CO}_{2}$

$0.1 M = n_{moles} \times \frac{1000}{100}$

$n_{moles} = 0.01 moles$

1 mole $H_{2} {SO}_{4} = 1 mole {CO}_{2}$

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