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Q.

How many lithium atoms are present in a unit cell with edge length 3.5 A0 having a density 0.54 g/cc (Atomic mass of Li = 6.94)

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a

2

b

1

c

6

d

4

answer is A.

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Detailed Solution

 d=Z×MNA×a3Z=a3×d×NAMZ=3.5×10−83×0.54×6.023×10236.94≈2

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