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Q.

How many litres of CO2 at STP will be formed when 100 ml of 0.1 M H2SO4 reacts with excess of Na2CO3?

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a

22.4

b

2.24

c

0.224

d

5.6

answer is C.

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Detailed Solution

Volume of H2SO4 = 100ml

Molarity of H2SO4 = 0.1m

large 0.1 = n_{H_2SO_4} times frac{1000}{100}

large n_{H_2SO_4} = 0.01

large mathop {mathop {{H_2}S{O_4}}limits^{1mole} }limits_{0.01} + mathop {N{a_2}C{O_3}}limits_{(excess)} to N{a_2}S{O_4} + {H_2}O + mathop {mathop {C{O_2}}limits^{22.4l} }limits_{'X'l}

 large Volume;of;CO_2;liberated;at;STP(X);=;frac{0.01 times 22.4}{1};lit

Vol of CO2 liberated at STP(X) = 0.224 lit

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