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How many litres of oxygen (at STP) are required for complete combustion of 39 gms of liquid Benzene? (Atomic weights: C = 12, H = 1, O = 16 )

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22.4

11.2

answer is A.

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Detailed Solution

$C_{6} H_{6} + 2 O_{2} \to 6 {CO}_{2} + 3 H_{2} O$

$\underset{Mass}{2 C_{6} H_{6}} + \underset{Volume}{15 O_{2}} \to 12 {CO}_{2} + 6 H_{2} O$

$2 \times 78 - 15 \times 22.4$

39-----x

$x = \frac{39 \times 15 \times 22.4}{2 \times 78}$

=84 L

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