How many millilitres of $0.1 M H_{2} {SO}_{4}$ must be added to 50ml of 0.1M NaOH to give a solution that has a concentration of 0.05M in $H_{2} {SO}_{4}$

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200ml

100ml

400ml

1000ml

answer is C.

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Detailed Solution

Let V be the volume of acid added

$\begin{matrix} N = \frac{(NV) acid - (NV) base}{V total} \\ 0.05 \times 2 = \frac{0.1 \times 2 \times V - 50 \times 0.1}{(V + 50)} \\ V = 100 ml \end{matrix}$

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