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How many ml of 1 (M) $H_{2} {SO}_{4}$ is required to neutralize 10 ml of 1 (M) NaOH solution ?

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Detailed Solution

$H_{2} {SO}_{4} + 2 NaOH \to {Na}_{2} {SO}_{4} + 2 H_{2} O$

$\begin{array}{l} (H_{2} {SO}_{4}) \frac{M_{1} V_{1}}{n_{1}} = \frac{M_{2} V_{2}}{n_{2}} (NaOH) \\ n_{1}, n_{2} are no . of moles from equation \\ \frac{1 \times V_{1}}{1} = \frac{1 \times 10}{2} \\ V_{1} = 5 ml . \end{array}$

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