How many molecules have $s{p}^{3}d$ hybridization of the central atoms in their transition state during hydrolysis process?

${\mathrm{PCl}}_3,{ \mathrm{PCl}}_5,{ \mathrm{SiCl}}_4,{ \mathrm{SF}}_4,{ \mathrm{CCl}}_4,{ \mathrm{BF}}_3,{ \mathrm{BCl}}_3,{\mathrm{TeF}}_6,{ \mathrm{BeCl}}_2$

For ${\mathrm{PCl}}_3$, three bond pairs and one lone pair are involved in the ${\mathrm{sp}}^3$ hybridization of the core atom, phosphorus. The shift in electrical configuration is caused by one of the electrons moving to an empty d orbital in the excited state.
The central$\mathrm{Si}$ atom in the molecule ${\mathrm{SiCl}}_4$ has four valence electrons, and since it is making four sigma bonds with the Cl atoms, the stearic number of $\mathrm{Si}$is four. This suggests that the molecule is ${\mathrm{sp}}^3$ hybridized, with tetrahedral geometry and shape.

The molecules which have $s{p}^{3}d$ hybridization of a central atom in their transition state during hydrolysis process are,

${\mathrm{PCl}}_3,{ \mathrm{SiCl}}_4$