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Q.

How many moles $H_{2} S O_{4}$ can be obtained from 1320 gm PbS as per reaction sequence?
$\begin{array}{l} 2 P b S + 3 O_{2} \to 2 P b O + 2 S O_{2} \\ 3 S O_{2} + 2 H N O_{3} + 2 H_{2} O \to 3 H_{2} S O_{4} + 2 N O \end{array}$
[ At. mass : Pb = 208, S=32]

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a

5.5

b

2.3

c

4.1

d

15.5

answer is A.

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Detailed Solution

Moles of PbS $= \frac{1320}{240} = 5.5 mol$
Moles of $S O_{2} = 5.5 mol = moles of H_{2} S O_{4}$

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