How many moles of ‘A’ can be produced by reaction of 0.1 moles of ‘X’, 0.36 moles of ‘Y’ and 0.9 moles of ‘Z’ according to the following reaction ?
4X + 18Y +30Z → 3A +2B+18C +30D

$$\begin{gathered} 4\mathrm{X} + 18\mathrm{Y} +30\mathrm{Z} \to 3\mathrm{A} +2\mathrm{B}+18\mathrm{C} +30\mathrm{D} \\ 0.1 0.36 0.9 \\ \mathrm{from} \mathrm{the} \mathrm{balenced} \mathrm{eq}. \mathrm{ratio} \mathrm{of} \mathrm{no}. \mathrm{of} \mathrm{moles}, \mathrm{x}:\mathrm{y}:\mathrm{z}=4:18:30=1:4.5:7.5 \\ =0.1:0.45:0.75 \\ \mathrm{So}, \text{'}\mathrm{Y}\text{'} \mathrm{is} \mathrm{the} \mathrm{limiting} \mathrm{reagent}. \\ \therefore \mathrm{no}. \mathrm{of} \mathrm{moles} \mathrm{of} \text{'}\mathrm{A}\text{'} \mathrm{formed}=\frac{0.36}{18}\times 3=0.06 \end{gathered}$$