How many moles of acidified $FeS{O}_4$ can be completely oxidized by one mole of $KMn{O}_4$

The balanced ionic equation:

$Mn{O_4}^{-}+8H^{+}+5F{e}^{2+}$$\to$$M{n}^{2+}+4H_{2}O+5F{e}^{2+}$

From the equation, one mole of $KMn{O}_4$ acidifies $5$ moles of $FeS{O}_4$.

Hence correct option is B.