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How many moles of He gas occupy 22.4 litres at $30^{0} C$ and one atmospheric pressure

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0.90

1.11

0.11

1.0

answer is A.

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Detailed Solution

$\frac{P_{1} V_{1}}{n_{1} T_{1}} = \frac{P_{2} V_{2}}{n_{2} T_{2}} ∴ n_{2} = \frac{P_{2} V_{2} T_{1}}{P_{1} V_{1} T_{2}}$

at STP $n_{1} =$ one mole at $T = 273^{0} + 30^{0} = 303^{0} K$

$\begin{array}{r} P_{1} = 1 a t m \\ V_{1} = 22.4 l t \\ T_{1} = 273^{0} K \end{array}\}$ $\begin{array}{l} P_{2} = 1 a t m \\ V_{2} = 22.4 \end{array}$

$n_{2} = \frac{1}{1} \times \frac{22.4}{22.4} \times \frac{273}{303} \times 1 = 0.9$ moles

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