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How many moles of magnesium phosphate, $M g_{3} {(P O_{4})}_{2}$ , will contain 0.25 moles of oxygen atoms?

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$1.25 \times 10^{- 2}$

0.02

$2.5 \times 10^{- 2}$

$3.125 \times 10^{- 2}$

answer is B.

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Detailed Solution

1 mol of ${mg}_{3} {({po}_{4})}_{3}$ contains -8 oxygen atoms
0.25 mole of oxygen contains ${mg}_{3} {({po}_{4})}_{3}$ is
$= \frac{0.25}{8} = 3.125 \times 10^{- 2}$

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