How many moles of magnesium phosphate, Mg3(PO4)2 will contain 0.25 mole of oxygen atoms ?

1 mole of Mg3(PO4)2 contains 8 mole atoms of O-atoms ? = 0.25 mole O-atoms=0.258=3.125 ×10-2

How many moles of magnesium phosphate, Mg3(PO4)2 will contain 0.25 mole of oxygen atoms ?

1 mole of Mg3(PO4)2 contains 8 mole atoms of O-atoms ? = 0.25 mole O-atoms=0.258=3.125 ×10-2

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How many moles of magnesium phosphate, Mg₃(PO₄)₂will contain 0.25 mole of oxygen atoms ?

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0.02

3.125 $\times$ 10^-2

1.25 $\times$ 10^-2

2.5 $\times$ 10^-2

answer is B.

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Detailed Solution

1 mole of Mg₃(PO₄)₂ contains 8 mole atoms of O-atoms

? = 0.25 mole O-atoms

= $\frac{0.25}{8} =$ 3.125 $\times$ 10^-2

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How many moles of magnesium phosphate, Mg3(PO4)2 will contain 0.25 mole of oxygen atoms ?

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How many moles of magnesium phosphate, Mg₃(PO₄)₂will contain 0.25 mole of oxygen atoms ?