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How many moles of ${Mg}_{3} (P O_{4})_{2}$ will contain $0.25$ mole of oxygen atoms?

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$1.25 \times 10^{- 2}$

$3.125 \times 10^{- 2}$

$0.02$

$2.5 \times 10^{- 2}$

answer is B.

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Detailed Solution

1 Mole of

$= \frac{0.25}{8} \times 1 = 0.03125 = 3.125 \times 10^{- 2}$

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